1132 Cut Integer (20 分)

1132 Cut Integer (20 分)
 

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <). It is guaranteed that the number of digits of Z is an even number.

Output Specification:

For each case, print a single line Yes if it is such a number, or No if not.

Sample Input:

3
167334
2333
12345678

Sample Output:

Yes
No
No

判断能否整除,注意ab可能为零

 1 #include <bits/stdc++.h>
 2 
 3 using namespace std;
 4 int n;
 5 string s;
 6 int main(){
 7     cin >> n;
 8     while(n--){
 9         int a = 0,b = 0,c = 0;
10         cin >> s;
11         int len = s.length();
12         for(int i = 0; i < len; i++){
13             c = c*10 + s[i]-'0';
14         }
15         for(int i = 0; i < len/2; i++){
16             a = a*10 + s[i]-'0';
17         }
18         for(int i = len/2; i < len; i++){
19             b = b*10 + s[i]-'0';
20         }
21         if(a*b != 0 && c%(a*b) == 0){
22             cout <<"Yes"<<endl;
23         }else{
24             cout <<"No"<<endl;
25         }
26 
27     }
28     return 0;
29 }





原文地址:https://www.cnblogs.com/zllwxm123/p/11305688.html