利用递归实现数组的扁平化

// 利用递归实现数组的扁平化
let ary = [1, [2, [3, [4, 5]]], 6];

let result = [];

let fn = function(ary){

  for(let i = 0 ; i < ary.length; i++){

    let item = ary[i]

    if(Array.isArray(ary[i])){

      fn(item);

    } else {

      result.push(item)

    }
  }
}
fn(ary);
console.log(result);

原文地址:https://www.cnblogs.com/zjz666/p/11088445.html