使用fastjson的parseObject方法将json字符串转换成Map 或者List

fastjson 转换成map

HashMap<String,String> map = JSON.parseObject(jsonStr,new TypeReference<HashMap<String,String>>() {});

 

fastjson 转换成list

List<Person> list = new ArrayList<Person>();  
list = JSON.parseArray(jasonArray.toString, Person.class);  

原文地址:https://www.cnblogs.com/zjm-1/p/9413908.html