UVa11462 Age Sort

B

Age Sort Input: Standard Input Output: Standard Output

 

You are given the ages (in years) of all people of a country with at least 1 year of age. You know that no individual in that country lives for 100 or more years. Now, you are given a very simple task of sorting all the ages in ascending order.

 

Input

There are multiple test cases in the input file. Each case starts with an integer n (0<n<=2000000), the total number of people. In the next line, there are n integers indicating the ages. Input is terminated with a case where n= 0. This case should not be processed.

 

Output

For each case, print a line with n space separated integers. These integers are the ages of that country sorted in ascending order.

 

Warning: Input Data is pretty big (~  25 MB) so use faster IO.

 

Sample Input                             Output for Sample Input

5 3 4 2 1 5 5 2 3 2 3 1 0

1 2 3 4 5 1 2 2 3 3

Note: The memory limit of this problem is 2 Megabyte Only.

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Problem Setter: Mohammad Mahmudur Rahman

Special Thanks: Shahriar Manzoor

题解：排序个数N=2000000,快排显然不行，因为题目中说人的寿命都会小于100岁，因此重复的很多，用计数排序可以完美的解决此问题。

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
long a[105];
long n;
int main(void)
{
    long i,k,flag;
    while(scanf("%ld",&n)!=EOF)
    {
        if(n==0) break;
        memset(a,0,sizeof(a));
        for(i=0; i<n; i++)
        {
            scanf("%ld",&k);
            a[k]++;
        }
        flag=1;
        for(i=1; i<=100; i++)
            while(a[i])
            {
               if(flag)
               {
                printf("%ld",i);
                flag=0;
               }
               else
               printf(" %ld",i);
                a[i]--;
            }
           printf("\n");
    }
    return 0;
}