BZOJ 2756 奇怪的游戏

1.二分+网络流+各种判。

2.网上很多程序都是错的。

3.一个%lld打成%d调了一年。

#include<iostream>
#include<cstdio>
#include<cstring>
#include<queue>
#include<algorithm>
#define maxn 45
#define maxv 1700
#define maxe 1000500
#define inf (1LL<<50)
using namespace std;
long long tt,n,m,map[maxn][maxn],col[maxn][maxn],n1=0,n2=0,s1=0,s2=0,mx=0;
long long dx[]={0,0,1,0,-1},dy[]={0,1,0,-1,0};
long long dis[maxv],nume=1,g[maxv],s,t;
queue <long long> q;
bool vis[maxv];
struct edge
{
    long long v,f,nxt;
}e[maxe];
long long p(long long x,long long y)
{
    return (x-1)*m+y;
}
void addedge(long long u,long long v,long long f)
{
    e[++nume].v=v;e[nume].f=f;e[nume].nxt=g[u];g[u]=nume;
    e[++nume].v=u;e[nume].f=0;e[nume].nxt=g[v];g[v]=nume;
}
bool checks(long long x,long long y)
{
    if ((x>=1) && (x<=n) && (y>=1) && (y<=m)) return true;
    return false;
}
void build(long long x)
{
    nume=1;memset(g,0,sizeof(g));
    s=0;t=n1+n2+1;
    for (long long i=1;i<=n;i++) 
        for (long long j=1;j<=m;j++)
        {
            long long now=p(i,j);
            if (col[i][j]) addedge(s,now,x-map[i][j]);
            else addedge(now,t,x-map[i][j]);
            if (col[i][j])
            {
                for (long long k=1;k<=4;k++)
                {
                    long long a=i+dx[k],b=j+dy[k],ret=p(a,b);
                    if (checks(a,b)) addedge(now,ret,inf);
                }
            }
        }
}
bool bfs()
{
    for (long long i=s;i<=t;i++) {dis[i]=inf;vis[i]=false;}
    q.push(s);dis[s]=0;vis[s]=true;
    while (!q.empty())
    {
        long long head=q.front();q.pop();
        for (long long i=g[head];i;i=e[i].nxt)
        {
            long long v=e[i].v;
            if ((e[i].f) && (dis[v]>dis[head]+1))
            {
                dis[v]=dis[head]+1;
                if (!vis[v]) {q.push(v);vis[v]=true;}
            }
        }
    }
    if (dis[t]==inf) return false;
    return true;
}
long long dinic(long long x,long long low)
{
    if (x==t) return low;
    long long ret=0;
    for (long long i=g[x];i && low;i=e[i].nxt)
    {
        long long v=e[i].v;
        if ((e[i].f) && (dis[v]==dis[x]+1))
        {
            long long dd=dinic(v,min(e[i].f,low));
            e[i].f-=dd;e[i^1].f+=dd;
            ret+=dd;low-=dd;
        }
    }
    if (!ret) dis[x]=inf;
    return ret;
}
bool check(long long x)
{
    build(x);
    long long max_flow=0,ret=0;
    while (bfs())
        max_flow+=dinic(s,inf);
    for (long long i=1;i<=n;i++)
        for (long long j=1;j<=m;j++)
            if (col[i][j]) ret+=(x-map[i][j]);
    if (ret==max_flow) return true;
    return false;
}
void work1()
{
    long long x=(s1-s2)/(n1-n2);
    if (x>=mx)
        if (check(x))
        {
            long long ret=x*(n1+n2)-s1-s2;
            printf("%lld
",(x*(n1+n2)-s1-s2)/2);
            return;
        }
    printf("-1
");
}
void work2()
{
    if (s1!=s2) {printf("-1
");return;}
    long long l=mx,r=inf,ans=inf;
    while (l<=r)
    {
        long long mid=l+r>>1;
        if (check(mid)) {ans=mid;r=mid-1;}
        else l=mid+1;
    }
    if (ans==inf) printf("-1
");
    else printf("%lld
",(ans*(n1+n2)-s1-s2)/2);
    return;
}
void work()
{
    n1=0;n2=0;s1=0;s2=0;mx=0;
    scanf("%lld%lld",&n,&m);
    for (long long i=1;i<=n;i++)
        for (long long j=1;j<=m;j++)
        {
            scanf("%lld",&map[i][j]);
            mx=max(mx,map[i][j]);
        }
    if ((n==1) && (m==1)) 
    {
        printf("0
");
        return;
    }
    col[1][1]=1;
    for (long long i=1;i<=n;i++)
        for (long long j=1;j<=m;j++)
            for (long long k=1;k<=4;k++)
                col[i+dx[k]][j+dy[k]]=col[i][j]^1;
    for (long long i=1;i<=n;i++)
        for (long long j=1;j<=m;j++)
        {
            if (col[i][j]) {n1++;s1+=map[i][j];}
            else {n2++;s2+=map[i][j];}
        }
    if (n1!=n2) work1();
    else work2();
}
int main()
{
    scanf("%lld",&tt);
    for (long long i=1;i<=tt;i++)
        work();
    return 0;
}
原文地址:https://www.cnblogs.com/ziliuziliu/p/5927275.html