Java [Leetcode 169]Majority Element

题目描述:

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.

You may assume that the array is non-empty and the majority element always exist in the array.

解题思路:

每找出两个不同的element,就成对删除即count--,最终剩下的一定就是所求的。时间复杂度:O(n)。

代码如下:

public class Solution {
    public int majorityElement(int[] nums) {
        int major = 0;
        int count = 0;
        for(int i = 0; i < nums.length; i++){
        	if(count == 0){
        		major = nums[i];
        		count++;
        	}else{
        		if(nums[i] == major)
        			count++;
        		else
        			count--;
        		if(count >= nums.length / 2 + 1)
        			return major;
        	}
        }
        return major;
    }
}

  

原文地址:https://www.cnblogs.com/zihaowang/p/5074617.html