formData的简单使用

var submitForm = new FormData();
submitForm.append("name",name);
submitForm.append("pass",pass);
//提交数组
for (var i=0;i<likes.length;i++){
    submitForm.append("likeList",likes[i]);
}
$.ajax({
    type:"POST",
    url:"#",
    data:submitForm,
    processData:false,
    contentType:false,
    success:function(result){
       
    }
})

ps：用来异步提交文件上传表单，上传文件