SQL练习题17:获取当前(to_date='9999-01-01')薪水第二多的员工的emp_no以及其对应的薪水salary

题目:

获取当前(to_date='9999-01-01')薪水第二多的员工的emp_no以及其对应的薪水salary
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

思路:

倒数第二用LIMIT 1 OFFSET 1来表示

程序:

SELECT emp_no, salary
FROM salaries
WHERE to_date = '9999-01-01'
ORDER BY salary DESC
LIMIT 1 OFFSET 1
原文地址:https://www.cnblogs.com/zhuozige/p/13715135.html