HDU-1255 覆盖的面积覆盖的矩形面积并

　　题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1255
　　需要保存区间覆盖线>=2的线段的长度，根据情况来更新。。。
  1 //STATUS:C++_AC_250MS_476KB
  2 #include <functional>
  3 #include <algorithm>
  4 #include <iostream>
  5 //#include <ext/rope>
  6 #include <fstream>
  7 #include <sstream>
  8 #include <iomanip>
  9 #include <numeric>
 10 #include <cstring>
 11 #include <cassert>
 12 #include <cstdio>
 13 #include <string>
 14 #include <vector>
 15 #include <bitset>
 16 #include <queue>
 17 #include <stack>
 18 #include <cmath>
 19 #include <ctime>
 20 #include <list>
 21 #include <set>
 22 #include <map>
 23 using namespace std;
 24 //using namespace __gnu_cxx;
 25 //define
 26 #define pii pair<int,int>
 27 #define mem(a,b) memset(a,b,sizeof(a))
 28 #define lson l,mid,rt<<1
 29 #define rson mid+1,r,rt<<1|1
 30 #define PI acos(-1.0)
 31 //typedef
 32 typedef __int64 LL;
 33 typedef unsigned __int64 ULL;
 34 //const
 35 const int N=2010;
 36 const int INF=0x3f3f3f3f;
 37 const int MOD=100000,STA=8000010;
 38 const LL LNF=1LL<<60;
 39 const double EPS=1e-8;
 40 const double OO=1e15;
 41 const int dx[4]={-1,0,1,0};
 42 const int dy[4]={0,1,0,-1};
 43 const int day[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
 44 //Daily Use ...
 45 inline int sign(double x){return (x>EPS)-(x<-EPS);}
 46 template<class T> T gcd(T a,T b){return b?gcd(b,a%b):a;}
 47 template<class T> T lcm(T a,T b){return a/gcd(a,b)*b;}
 48 template<class T> inline T lcm(T a,T b,T d){return a/d*b;}
 49 template<class T> inline T Min(T a,T b){return a<b?a:b;}
 50 template<class T> inline T Max(T a,T b){return a>b?a:b;}
 51 template<class T> inline T Min(T a,T b,T c){return min(min(a, b),c);}
 52 template<class T> inline T Max(T a,T b,T c){return max(max(a, b),c);}
 53 template<class T> inline T Min(T a,T b,T c,T d){return min(min(a, b),min(c,d));}
 54 template<class T> inline T Max(T a,T b,T c,T d){return max(max(a, b),max(c,d));}
 55 //End
 56 
 57 struct Seg{
 58     double y,x1,x2;
 59     int c;
 60     Seg(){}
 61     Seg(double a,double b,double c,int d):y(a),x1(b),x2(c),c(d){}
 62     bool operator < (const Seg& a)const{
 63         return y<a.y;
 64     }
 65 }seg[N];
 66 double hs[N],len[N<<2][2];
 67 int cnt[N<<2];
 68 int T,n,m;
 69 
 70 void pushup(int l,int r,int rt)
 71 {
 72     if(cnt[rt])len[rt][0]=hs[r+1]-hs[l];
 73     else if(l==r)len[rt][0]=0;
 74     else len[rt][0]=len[rt<<1][0]+len[rt<<1|1][0];
 75     if(cnt[rt]>=2)len[rt][1]=len[rt][0];
 76     else if(cnt[rt]==1)len[rt][1]=len[rt<<1][0]+len[rt<<1|1][0];
 77     else if(l==r)len[rt][1]=0;
 78     else len[rt][1]=len[rt<<1][1]+len[rt<<1|1][1];
 79 }
 80 
 81 void update(int a,int b,int c,int l,int r,int rt)
 82 {
 83     if(a<=l && r<=b){
 84         cnt[rt]+=c;
 85         pushup(l,r,rt);
 86         return;
 87     }
 88     int mid=(l+r)>>1;
 89     if(a<=mid)update(a,b,c,lson);
 90     if(b>mid)update(a,b,c,rson);
 91     pushup(l,r,rt);
 92 }
 93 
 94 int binary(int l,int r,double tar)
 95 {
 96     int mid;
 97     while(l<r){
 98         mid=(l+r)>>1;
 99         if(hs[mid]==tar)return mid;
100         else if(hs[mid]>tar)r=mid;
101         else l=mid+1;
102     }
103     return -1;
104 }
105 
106 int main()
107 {
108  //   freopen("in.txt","r",stdin);
109     int i,j,k,l,r;
110     double ans,a,b,c,d;
111     scanf("%d",&T);
112     while(T--)
113     {
114         scanf("%d",&n);
115         m=0;
116         for(i=0;i<n;i++){
117             scanf("%lf%lf%lf%lf",&a,&b,&c,&d);
118             hs[m]=a;
119             seg[m++]=Seg(b,a,c,1);
120             hs[m]=c;
121             seg[m++]=Seg(d,a,c,-1);
122         }
123         sort(hs,hs+m);
124         sort(seg,seg+m);
125         for(i=1,k=0;i<m;i++)
126             if(hs[i]!=hs[k])hs[++k]=hs[i];
127         mem(len,0);mem(cnt,0);
128         ans=0;
129         for(i=0;i<m-1;i++){
130             l=binary(0,k+1,seg[i].x1);
131             r=binary(0,k+1,seg[i].x2)-1;
132             if(l<=r)update(l,r,seg[i].c,0,k,1);
133             ans+=len[1][1]*(seg[i+1].y-seg[i].y);
134         }
135 
136         printf("%.2lf
",ans);
137     }
138     return 0;
139 }
HDU-1255 覆盖的面积 覆盖的矩形面积并

HDU-1255 覆盖的面积覆盖的矩形面积并
