点到原点的距离(继承)

给出下面的一个基类框架:

class Point_1D

{ protected:

float x;//1D 点的x坐标

public:

Point_1D(float p = 0.0);

float distance( );//计算当前点到原点的距离

}

以Point_1D为基类建立一个派生类Point_2D,增加一个保护数据成员:

float y;//2D平面上点的y坐标

以Point_2D为直接基类再建立一个派生类Point_3D,增加一个保护数据成员:

float z;//3D立体空间中点的z坐标

生成上述类并编写主函数,根据输入的点的基本信息,建立点对象,并能计算该点到原点的距离。

输入格式: 测试输入包含若干测试用例,每个测试用例占一行(点的类型(1表示1D点,2表示2D点,3表示3D点) 第一个点坐标信息(与点的类型相关) 第二个点坐标信息(与点的类型相关))。当读入0时输入结束,相应的结果不要输出。

输入样例:

1 -1

2 3 4

3 1 2 2

0

输出样例:

Distance from Point -1 to original point is 1

Distance from Point(3,4) to original point is 5

Distance from Point(1,2,2) to original point is 3

实现如下:

#include<iostream>
#include<math.h>
using namespace std;
class Point_1D
{
protected:
float x;//1D 点的x坐标
public:
//Point_1D(float p = 0.0);
void set_1D(){cin>>x;}
Point_1D(float a=0){x=a;}
float distance(const Point_1D & p2);
};
class Point_2D:public Point_1D
{
protected:
float y;//2D平面上点的y坐标
public:
Point_2D(float a=0,float b=0){x=a;y=b;}
void set_2D(){set_1D();cin>>y;}
float distance(const Point_2D & p2);
};
class Point_3D:public Point_2D
{
protected:
float z;//3D立体空间中点的z坐标
public:
Point_3D(float a=0,float b=0,float c=0){x=a;y=b;z=c;}
void set_3D(){set_2D();cin>>z;}
float distance(const Point_3D & p2);
};
int main()
{
int type;
Point_1D a1,a2;
Point_2D b1,b2;
Point_3D c1,c2;
cin>>type;
while(type)
{
switch(type)
{
case 1:a1.set_1D();a1.distance(a2);break;
case 2:b1.set_2D();b1.distance(b2);break;
case 3:c1.set_3D();c1.distance(c2);break;
}
cin>>type;
}
return 0;
}
float Point_1D::distance(const Point_1D & p2)
{
float a;
a=fabs(x-p2.x);
cout<<"Distance from Point "<<x<<" to original point is "<<a<<endl;
return a;
}
float Point_2D::distance(const Point_2D & p2)
{
float a;
a=sqrt((x-p2.x)*(x-p2.x)+(y-p2.y)*(y-p2.y));
cout<<"Distance from Point("<<x<<","<<y<<") to original point is "<<a<<endl;
return a;
}
float Point_3D::distance(const Point_3D & p2)
{
float a;
a=sqrt((x-p2.x)*(x-p2.x)+(y-p2.y)*(y-p2.y)+(z-p2.z)*(z-p2.z));
cout<<"Distance from Point("<<x<<","<<y<<","<<z<<") to original point is "<<a<<endl;
return a;
}

原文地址:https://www.cnblogs.com/zhouqianwei/p/8963090.html