递归求1-100之和

递归求1-100之和
/*
    *求1-100之和
*/

function sum(num1, num2) {
    var num = num1 + num2;

    if (num2 + 1 > 100) {
        return num;
    } else {
        return sum(num, num2 + 1)
    }

}
var sum = sum(1, 2);   
console.log("sum ...",sum);
未完,待续......
原文地址:https://www.cnblogs.com/zhishiyv/p/14638267.html