http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2971
题意：将输入的英文数字表达转化为阿拉伯数字。
1 #include<bits/stdc++.h> 2 using namespace std; 3 4 char aa[30][10]= {"zero", "one","two", "three", "four", "five", "six", "seven", "eight", "nine", 5 "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen","nineteen", 6 "twenty","thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety" 7 }; 8 int bb[28]= {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,30,40,50,60,70,80,90}; 9 char cc[300][20]; 10 int main() { 11 int t; 12 char s[250]; 13 scanf("%d",&t); 14 getchar();//先吃掉t后面的回车 15 while(t--) { 16 memset(s,0,sizeof(s)); 17 memset(cc,0,sizeof(cc)); 18 gets(s); 19 int num=0,k=0; 20 int len=strlen(s); 21 for(int i=0; i<len; i++) { 22 if(i>=1&&s[i]==' '&&s[i-1]!=' ') { 23 num++;//在’ ‘前算上一个字符串 24 k=0; 25 continue; 26 } 27 if(s[i]!=' ') 28 cc[num][k++]=s[i];//装入一个字符串 29 } 30 int sum1=0,sum2=0; 31 int j;
//有前至后读入字符串 32 for(int i=0; i<=num; i++) { 33 for(j=0; j<28; j++) { 34 if(strcmp(cc[i],aa[j])==0) { 35 sum1+=bb[j]; 36 break; 37 } 38 } 39 if(j=28) { 40 if(strcmp(cc[i],"and")==0) 41 continue; 42 if(strcmp(cc[i],"thousand")==0) { 43 sum1*=1000; 44 sum2+=sum1; 45 sum1=0; 46 } else if(strcmp(cc[i],"hundred")==0) 47 sum1*=100; 48 else if(strcmp(cc[i],"million")==0) { 49 sum1*=1000000; 50 sum2+=sum1; 51 sum1=0; 52 } 53 } 54 } 55 printf("%d ",sum2+sum1); 56 } 57 return 0; 58 }//善于使用strcmp函数，其实想到就很简单了