HD1556Color the ball(树状数组)

Color the ball

Time Limit: 9000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 13645    Accepted Submission(s): 6850


Problem Description
N个气球排成一排,从左到右依次编号为1,2,3....N.每次给定2个整数a b(a <= b),lele便为骑上他的“小飞鸽"牌电动车从气球a开始到气球b依次给每个气球涂一次颜色。但是N次以后lele已经忘记了第I个气球已经涂过几次颜色了,你能帮他算出每个气球被涂过几次颜色吗?
 
Input
每个测试实例第一行为一个整数N,(N <= 100000).接下来的N行,每行包括2个整数a b(1 <= a <= b <= N)。
当N = 0,输入结束。
 
Output
每个测试实例输出一行,包括N个整数,第I个数代表第I个气球总共被涂色的次数。
 
Sample Input
3 1 1 2 2 3 3 3 1 1 1 2 1 3 0
 
Sample Output
1 1 1 3 2 1
 
Author
8600
 

 树状数组搞定的第一题!

 1 #include <iostream>
 2 #include <cstring>
 3 #include <cstdio>
 4 #include <algorithm>
 5 using namespace std;
 6 const int MAX = 100000 + 10;
 7 int c[MAX];
 8 int n;
 9 int lowbit(int k)
10 {
11     return k & (-k);
12 }
13 void update(int x,int num)
14 {
15 
16     while(x <= n)
17     {
18         c[x] += num;
19         x += lowbit(x);
20     }
21 }
22 int sum(int x)
23 {
24     int s = 0;
25     while(x > 0)
26     {
27         s += c[x];
28         x -= lowbit(x);
29     }
30     return s;
31 }
32 int main()
33 {
34     while(scanf("%d", &n) && n)
35     {
36         int a,b;
37         memset(c,0,sizeof(c));
38         for(int i = 0; i < n; i++)
39         {
40             scanf("%d%d",&a,&b);
41             update(a,1);
42             update(b + 1,-1);
43         }
44         printf("%d",sum(1));
45         for(int i = 2; i <= n; i++)
46             printf(" %d",sum(i));
47         printf("
");
48     }
49     return 0;
50 }
View Code
原文地址:https://www.cnblogs.com/zhaopAC/p/4967261.html