hduoj1042N!

View Code
#include<stdio.h>
#include<string.h>
#define maxn 40000
int c[maxn];
int main()
{
    int i,j,s,k,n;
    
    while(scanf("%d",&n)!=EOF)
    {
        memset(c,0,sizeof(c));
         c[0]=1; k=0;
       for(i=2;i<=n;i++)
       {   
           for(j=0;j<maxn;j++)
           {
               s=c[j]*i+k;
               c[j]=s%10;
               k=s/10;
           }
       }
       for(i=maxn-1;i>=0;i--)
           if(c[i])break;
           for(j=i;j>=0;j--)
               printf("%d",c[j]);
           printf("\n");
    }
    return 0;
}

N!

Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 33293    Accepted Submission(s): 9225


Problem Description
Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N!
 
Input
One N in one line, process to the end of file.
 
Output
For each N, output N! in one line.
 
Sample Input
1 2 3
 
Sample Output
1 2 6
原文地址:https://www.cnblogs.com/zhaojiedi1992/p/zhaojiedi_2012_07_22.html