python求3的倍数与和

suqares=[]
i=1
sum=0
while i<=100:
    i+=1
    if i*3:
        sum=sum+i
        # print(i)
    suqares.append(i*3)
    # print(suqares.count())
print(suqares)
# print(len(suqares))
print(sum)
原文地址:https://www.cnblogs.com/zhangzihong/p/6113546.html