sdut2169:Sequence(dp)

题目:http://acm.sdut.edu.cn/sdutoj/problem.php?action=showproblem&problemid=2169

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <algorithm>
#define inf 0x3f3f3f3f
typedef long long ll;
using namespace std;
ll n,m;
ll sum;
ll w[1010],num[1010],dp[1010];
int main()
{
    int T;
    scanf("%d",&T);
    while(T--)
    {
        sum=0;
        scanf("%lld%lld",&n,&m);
        memset(num,0,sizeof(num));
        for(int i=1;i<=n;i++)
        {
           scanf("%d",&w[i]);
           num[i]=num[i-1]+w[i];
           dp[i]=num[i]*num[i];
           sum+=w[i];
        }
        if(m==1)
        {
            sum=sum*sum;
            printf("%lld
",sum);
            continue;
        }
        bool F=false;
        for(int j=2;j<=m;j++)
        {
            for(int i=n-m+j;i>=j;i--)
            {
                for(int k=j-1;k<i;k++)
                {
                    dp[i]=min(dp[i],(dp[k]+(num[i]-num[k])*(num[i]-num[k])));
                     if(j==m&&k==i-1)
                     {
                            F=true;
                            break;
                     }
                }
                if(F) break;
            }
        }
        printf("%lld
",dp[n]);
    }
    return 0;
}
 
原文地址:https://www.cnblogs.com/zhangmingcheng/p/4391831.html