hduPiggy-Bank(完全背包)

  http://acm.hdu.edu.cn/showproblem.php?pid=1114

此题就是最简单的完全背包，顺序！！！

for i=1..N

    for v=0..V

        f[v]=max{f[v],f[v-cost]+weight}

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define N 1000001
int dp[10005];
int main()
{
    int T,E,V,n;
    int w[502],v[502];
    scanf("%d",&T);
    while(T--)
    {
       scanf("%d%d",&E,&V);
       V=V-E;
       scanf("%d",&n);
       for(int i=1;i<=n;i++)
       {
           scanf("%d%d",&v[i],&w[i]);
       }
       for(int i=0;i<=V;i++)
         dp[i]=N;
         dp[0]=0;
       for(int i=1;i<=n;i++)
       {
           for(int j=w[i];j<=V;j++)
           {
               if(dp[j-w[i]]+v[i]<dp[j])
                  dp[j]=dp[j-w[i]]+v[i];
           }
       }
       if(dp[V]==N) printf("This is impossible.
");
       else printf("The minimum amount of money in the piggy-bank is %d.
",dp[V]);
    }
    return 0;
}