codeforces 709C C. Letters Cyclic Shift(贪心)

题目链接:

C. Letters Cyclic Shift

题意:

现在一串小写的英文字符,每个字符可以变成它前边的字符即b-a,c-a,a-z这样,选一个字串变换,使得得到的字符串字典序最小;

思路:

贪心,尽量让前边的字典序变小;

AC代码:

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <bits/stdc++.h>
#include <stack>
#include <map>
 
using namespace std;
 
#define For(i,j,n) for(int i=j;i<=n;i++)
#define mst(ss,b) memset(ss,b,sizeof(ss));
 
typedef  long long LL;
 
template<class T> void read(T&num) {
    char CH; bool F=false;
    for(CH=getchar();CH<'0'||CH>'9';F= CH=='-',CH=getchar());
    for(num=0;CH>='0'&&CH<='9';num=num*10+CH-'0',CH=getchar());
    F && (num=-num);
}
int stk[70], tp;
template<class T> inline void print(T p) {
    if(!p) { puts("0"); return; }
    while(p) stk[++ tp] = p%10, p/=10;
    while(tp) putchar(stk[tp--] + '0');
    putchar('
');
}
 
const LL mod=1e9+7;
const double PI=acos(-1.0);
const int inf=1e9;
const int N=1e5+10;
const int maxn=1e3+20;
const double eps=1e-12;

char s[N];

int main()
{
    scanf("%s",s);
    int len=strlen(s),flag=0;
    for(int i=0;i<len;i++)
    {
        if(s[i]!='a')
        {
            s[i]=s[i]-1;
            flag=1;
            continue;
        }
        else 
        {
            if(flag==0)continue;
            else break;
        }
    }
    if(flag==0)
    {
        s[len-1]='z';
    }
    for(int i=0;i<len;i++)printf("%c",s[i]);
    
    return 0;
}

  

原文地址:https://www.cnblogs.com/zhangchengc919/p/5806122.html