极验

#

from selenium import webdriver
from selenium.webdriver import ActionChains
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.wait import WebDriverWait
from PIL import Image
import time

def get_snap():
    '''
    对整个网页截图,保存成图片,然后用PIL.Image拿到图片对象
    :return: 图片对象
    '''
    driver.save_screenshot('snap.png')
    page_snap_obj=Image.open('snap.png')
    return page_snap_obj

def get_image():
    '''
    从网页的网站截图中,截取验证码图片
    :return: 验证码图片
    '''
    img=wait.until(EC.presence_of_element_located((By.CLASS_NAME,'geetest_canvas_img')))
    time.sleep(2) #保证图片刷新出来
    localtion=img.location
    size=img.size

    top=localtion['y']
    bottom=localtion['y']+size['height']
    left=localtion['x']
    right=localtion['x']+size['width']

    page_snap_obj=get_snap()
    crop_imag_obj=page_snap_obj.crop((left,top,right,bottom))
    return crop_imag_obj


def get_distance(image1,image2):
    '''
    拿到滑动验证码需要移动的距离
    :param image1:没有缺口的图片对象
    :param image2:带缺口的图片对象
    :return:需要移动的距离
    '''
    threshold=60
    left=57
    for i in range(left,image1.size[0]):
        for j in range(image1.size[1]):
            rgb1=image1.load()[i,j]
            rgb2=image2.load()[i,j]
            res1=abs(rgb1[0]-rgb2[0])
            res2=abs(rgb1[1]-rgb2[1])
            res3=abs(rgb1[2]-rgb2[2])
            if not (res1 < threshold and res2 < threshold and res3 < threshold):
                return i-7 #经过测试,误差为大概为7
    return i-7 #经过测试,误差为大概为7


def get_tracks(distance):
    '''
    拿到移动轨迹,模仿人的滑动行为,先匀加速后匀减速
    匀变速运动基本公式:
    ①v=v0+at
    ②s=v0t+½at²
    ③v²-v0²=2as

    :param distance: 需要移动的距离
    :return: 存放每0.3秒移动的距离
    '''
    #初速度
    v=0
    #单位时间为0.2s来统计轨迹,轨迹即0.2内的位移
    t=0.3
    #位移/轨迹列表,列表内的一个元素代表0.2s的位移
    tracks=[]
    #当前的位移
    current=0
    #到达mid值开始减速
    mid=distance*4/5

    while current < distance:
        if current < mid:
            # 加速度越小,单位时间的位移越小,模拟的轨迹就越多越详细
            a= 2
        else:
            a=-3

        #初速度
        v0=v
        #0.2秒时间内的位移
        s=v0*t+0.5*a*(t**2)
        #当前的位置
        current+=s
        #添加到轨迹列表
        tracks.append(round(s))

        #速度已经达到v,该速度作为下次的初速度
        v=v0+a*t
    return tracks


try:
    driver=webdriver.Chrome()
    driver.get('https://account.geetest.com/login')
    wait=WebDriverWait(driver,10)

    # 步骤八:完成登录
    input_email = driver.find_element_by_xpath('//*[@id="base"]/div[2]/div/div[2]/div[3]/div/form/div[1]/div/div[1]/div/input')
    input_password = driver.find_element_by_xpath('//*[@id="base"]/div[2]/div/div[2]/div[3]/div/form/div[2]/div/div[1]/div/input')

    input_email.send_keys('18611453110@163.com')
    input_password.send_keys('linhaifeng123')
    # 步骤一:先点击按钮,弹出没有缺口的图片
    button = wait.until(EC.presence_of_element_located((By.CLASS_NAME, 'geetest_radar_tip')))
    button.click()


    button = wait.until(EC.element_to_be_clickable((By.CLASS_NAME, 'geetest-btn')))


    # button.send_keys(Keys.ENTER)
    button.click()


    #步骤二:拿到没有缺口的图片
    image1=get_image()

    #步骤三:点击拖动按钮,弹出有缺口的图片
    button=wait.until(EC.presence_of_element_located((By.CLASS_NAME,'geetest_slider_button')))
    button.click()

    #步骤四:拿到有缺口的图片
    image2=get_image()

    # print(image1,image1.size)
    # print(image2,image2.size)

    #步骤五:对比两张图片的所有RBG像素点,得到不一样像素点的x值,即要移动的距离
    distance=get_distance(image1,image2)

    #步骤六:模拟人的行为习惯(先匀加速拖动后匀减速拖动),把需要拖动的总距离分成一段一段小的轨迹
    tracks=get_tracks(distance)
    print(tracks)
    print(image1.size)
    print(distance,sum(tracks))


    #步骤七:按照轨迹拖动,完全验证
    button=wait.until(EC.presence_of_element_located((By.CLASS_NAME,'geetest_slider_button')))
    ActionChains(driver).click_and_hold(button).perform()
    for track in tracks:
        ActionChains(driver).move_by_offset(xoffset=track,yoffset=0).perform()
    else:
        ActionChains(driver).move_by_offset(xoffset=3,yoffset=0).perform() #先移过一点
        ActionChains(driver).move_by_offset(xoffset=-3,yoffset=0).perform() #再退回来,是不是更像人了

    time.sleep(0.5) #0.5秒后释放鼠标
    ActionChains(driver).release().perform()

    # import time
    # time.sleep(200)
finally:
    print(1)
    # driver.close()
原文地址:https://www.cnblogs.com/zhangchen-sx/p/11166385.html