1077. Kuchiguse (20)

The Japanese language is notorious for its sentence ending particles. Personal preference of such particles can be considered as a reflection of the speaker's personality. Such a preference is called "Kuchiguse" and is often exaggerated artistically in Anime and Manga. For example, the artificial sentence ending particle "nyan~" is often used as a stereotype for characters with a cat-like personality:

Itai nyan~ (It hurts, nyan~)

Ninjin wa iyada nyan~ (I hate carrots, nyan~)

Now given a few lines spoken by the same character, can you find her Kuchiguse?

Input Specification:

Each input file contains one test case. For each case, the first line is an integer N (2<=N<=100). Following are N file lines of 0~256 (inclusive) characters in length, each representing a character's spoken line. The spoken lines are case sensitive.

Output Specification:

For each test case, print in one line the kuchiguse of the character, i.e., the longest common suffix of all N lines. If there is no such suffix, write "nai".

Sample Input 1:

3
Itai nyan~
Ninjin wa iyadanyan~
uhhh nyan~

Sample Output 1:

nyan~

Sample Input 2:

3
Itai!
Ninjinnwaiyada T_T
T_T

Sample Output 2:

nai

题目的意思是寻找最大公共后缀，直接模拟一下。

//		freopen("C:\Users\Administrator\Desktop\in.txt","r",stdin);
#include <iostream>
#include <map>
#include <queue>
#include <stdio.h>
#include <vector>
#include <algorithm>
#include <stack>
#include <stdlib.h>
#include <string.h>
#include <math.h>
#include <string>
using namespace std;

int n,mi;
int num;

struct E 
{
	int l;
	string s;
}stu[300];

int p(int num){
	int i,j;
	num=0;
	for(i=0;i<mi;i++){
		for( j=1;j<n;j++){
			if(stu[j].s[stu[j].l-i-1] != stu[j-1].s[stu[j-1].l-i-1]){
				return num;
			}
		}
		num++;
	}
	return num;
}

int main(){
//	freopen("C:\Users\Administrator\Desktop\in.txt","r",stdin);
	int i;
	cin>>n;
	getchar();
	mi=3000;
	for(i=0;i<n;i++){
		getline(cin,stu[i].s);
	//	cout<<stu[i].s<<endl;
		stu[i].l=stu[i].s.length();
		if(stu[i].l<mi){
			mi=stu[i].l;
		}
	}
	int ll;
	ll=p(0);
	if(ll==0)cout<<"nai"<<endl;
	else{
		for(i=0;i<ll;i++)
			cout<<stu[1].s[stu[1].l-ll+i];
		cout<<endl;
	}
	return 0;
}