js验证连续两位数字递增或递减和连续三位数字相同

<!DOCTYPE html>
<html>
<head lang="en">
<meta charset="UTF-8">
<title></title>
</head>
<body>
<form method="post" class="form-horizontal" role="form" action="" id="myform">
<input id="testid" name="testid" value='' >
<button onclick="f($('#testid').val())" type="button" id="smsbtn" class="btn btn-success">验证</button>
</form>
<script language="JavaScript">
function isPassword(){//连续三位数字相同
var str = $("#testid").val();
//var patrn=/(.)*(.)2{2}(.)*/g;
var patrn = /(w)*(w)2{2}(w)*/g;
if (patrn.test(str)){
alert('ture') //verify false
}else{
alert('false'); //verify true
}
}
function f(a){ //连续2位数字递增或递减
//console.log(a);
if(a.length<2){
return alert('111');
}
var t=a.charCodeAt(0)-a.charCodeAt(1);
console.log(t);
for(var i=0;i<a.length-1;i++){
if((a.charCodeAt(i)-a.charCodeAt(i+1))==-1 || (a.charCodeAt(i)-a.charCodeAt(i+1))==1 ){
return alert('true') //verify false
}else{
return alert('false') //verify true
}
}
}


</script>
<script src="js/jquery-1.11.3.js"></script>
</body>
</html>
原文地址:https://www.cnblogs.com/zh719588366/p/6260625.html