[模板] 负环

spfa求负环,玄学复杂度


int head[MAXN] = {0}, tot = 0;

void init(){ mem(head); tot = 0; }

struct node { int from, to, val, nex; } edge[MAXN << 1];

int add(int x, int y, int z)
{
	edge[++tot].to = y;
	edge[tot].val = z;
	edge[tot].nex = head[x];
	head[x] = tot;
	return tot;
}

int dis[MAXN], cnt[MAXN] = {0};

bitset <MAXN> used;

bool spfa(int x)
{
	memset(dis, 63, sizeof(dis));
	used.reset();
	mem(cnt);
		
	queue <int> Q;
	Q.push(x);
	
	used[x] = true;
	dis[x] = 0;
	cnt[x] = 1;
	
	while(!Q.empty())
	{
		int now = Q.front();
		Q.pop();
		used[now] = false;
		
		for(int it = head[now]; it; it = edge[it].nex)
		{
			int to = edge[it].to, val = edge[it].val;
			if(dis[to] > dis[now] + val)
			{
				dis[to] = dis[now] + val;
				cnt[to] = cnt[now] + 1;
				
				if(cnt[to] > n)
					return false; 
					
				if(!used[to])
					Q.push(to), used[to] = true;
			}
		}	
	}
	
	return true;
}
原文地址:https://www.cnblogs.com/zeolim/p/12270344.html