Cutie Pie

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Consider a NxM small-letters grid. SVU asked you to check whether this grid is a Cutie Pie or not A grid is a cutie pie if you can find the word "pie" in any direction (vertical, horizontal, and radial). Your program should output "Cutie Pie!" if the grid contains the word "pie" or "Sorry Man" otherwise

Input

The first line contains T 1<=T<=10000 the number of test cases. The followed T lines represent the test cases, each one contains two integers 0 < N,M  ≤  20 then N lines each of them contains M English small-letter separated by space characters. There is a blank line between each two successive test cases.

Output

For each test case output "Cutie Pie!" if the grid in the test case contains the word "pie" or "Sorry Man" otherwise.

Examples

input

Copy

2
3 5
o p r d t
i i i i e
f f s e d

4 3
o p r
o k r
i i u
f f s

output

Copy

Cutie Pie!
Sorry Man
<span style="color:#880000">本想用深搜做的,但能力有限,还是直接暴力过吧(虽然不是自己亲自做的^^)</span>
#include <bits/stdc++.h>
int main()
{
    int t;
    scanf("%d",&t);
    while(t--)
    {
        int a,b;
        scanf("%d%d",&a,&b);
        char s[30][30];
        for(int i=0; i<a; i++)
        {
            for(int j=0; j<b; j++)
            {
                scanf(" %c",&s[i][j]);
            }
        }
        int flag=0;
        for(int i=0; i<a; i++)
        {
            for(int j=0; j<b; j++)
            {
                if(s[i][j]=='p')
		   if((s[i-1][j]=='i'&&s[i-2][j]=='e')||(s[i+1][j]=='i'&&s[i+2][j]=='e')||(s[i][j-1]=='i'&&s[i][j-2]=='e')||(s[i][j+1]=='i'&&s[i][j+2]=='e')||(s[i+1][j+1]=='i'&&s[i+2][j+2]=='e')||(s[i-1][j-1]=='i'&&s[i-2][j-2]=='e')||(s[i+1][j-1]=='i'&&s[i+2][j-2]=='e')||(s[i-1][j+1]=='i'&&s[i-2][j+2]=='e'))
						flag=1;
            }
        }
        if(flag)
			printf("Cutie Pie!
");
		else
			printf("Sorry Man
");
    }
    return 0;
} <bits/stdc++.h>
int main()
{
    int t;
    scanf("%d",&t);
    while(t--)
    {
        int a,b;
        scanf("%d%d",&a,&b);
        char s[30][30];
        for(int i=0; i<a; i++)
        {
            for(int j=0; j<b; j++)
            {
                scanf(" %c",&s[i][j]);
            }
        }
        int flag=0;
        for(int i=0; i<a; i++)
        {
            for(int j=0; j<b; j++)
            {
                if(s[i][j]=='p')
		   if((s[i-1][j]=='i'&&s[i-2][j]=='e')||(s[i+1][j]=='i'&&s[i+2][j]=='e')||(s[i][j-1]=='i'&&s[i][j-2]=='e')||(s[i][j+1]=='i'&&s[i][j+2]=='e')||(s[i+1][j+1]=='i'&&s[i+2][j+2]=='e')||(s[i-1][j-1]=='i'&&s[i-2][j-2]=='e')||(s[i+1][j-1]=='i'&&s[i+2][j-2]=='e')||(s[i-1][j+1]=='i'&&s[i-2][j+2]=='e'))
						flag=1;
            }
        }
        if(flag)
			printf("Cutie Pie!
");
		else
			printf("Sorry Man
");
    }
    return 0;
}
原文地址:https://www.cnblogs.com/zcy19990813/p/9702819.html