asp_UpdatePanel PostBack返回后执行Javascript

Aspx页面代码

<%@ Page Language="C#" AutoEventWireup="true" %>

<html>

<head><title>UpdatePanel Call Javascript</title></head>

<body>

    <form id="form1" runat="server">

        <asp:ScriptManager ID="ScriptManager2" runat="server">

        </asp:ScriptManager>

        <asp:UpdatePanel ID="UpdatePanel10" runat="server">

            <ContentTemplate>

                <asp:Button ID="Button1" runat="server" Text="Button"

                onclick="Button1_Click" />

            </ContentTemplate>

        </asp:UpdatePanel>

    </form>

    </body>

    </html>

.cs代码

protected void Button1_Click(object sender, EventArgs e)

          //GoToListPage();

          string url = “pageList.aspx”;

          string js = "document.location.href ='" + url + "'";

          //string js = "alert('aa')";

          ScriptManager.RegisterStartupScript(this.Page, this.GetType(), "returnPageList", js, true);

注意：js代码不能写成如下格式（页面提示错误）

即不能加"<script language=javascript></script>“

public void ShowMessage(Type type, ClientScriptManager scriptManager, string message)

           if (!string.IsNullOrEmpty(message))

               scriptManager.RegisterStartupScript(type, "back", "<script language=javascript>alert('"+message+"');</script>");