用宏 x y z,找出最大值最小值

#define max(x,y,z) ((x)>(y)?(x):(y))>(z)?((x)>(y)?(x):(y)):(z)

#define min(x,y,z) ((x)<(y)?(x):(y))<(z)?((x)<(y)?(x):(y)):(z)

#include <stdio.h>
#define max(x,y,z) ((x)>(y)?(x):(y))>(z)?((x)>(y)?(x):(y)):(z)

#define min(x,y,z) ((x)<(y)?(x):(y))<(z)?((x)<(y)?(x):(y)):(z)

int main(void)
{
    unsigned int a,b;
    a = min(3,1,6);
    b = max(6,7,8);
    printf("a=%d
",a);
    printf("b=%d
",b);
    return 0;
}

  

原文地址:https://www.cnblogs.com/yygsj/p/5784360.html