hdu5240

想了辣么多 貌似就一个条件

#include<bits/stdc++.h>
using namespace std;
int flag=0;int main(){int t,n,kase=1;scanf("%d",&t);while(t--){flag=0;scanf("%d",&n);for(int i=0;i<n;i++){int r,e,l;scanf("%d%d%d",&r,&e,&l);if(e < r) flag=1;
}printf("Case #%d: ",kase++);if(flag) printf("NO
"); else printf("YES
");}return 0;}


原文地址:https://www.cnblogs.com/yutingliuyl/p/6910180.html