GridView中实现CheckBox的全选 (ajax)

根据一位网友的代码修改了一下
用服务器端的方法：
在页面上放一个gridview控件，配置好数据源，编辑列，添加一个模版列，再编辑模版，放入一个checkbox控件。代码如下：

<body>

<asp:ScriptManager ID="ScriptManager1" runat="server"/>

<div>

<asp:UpdatePanel ID="UpdatePanel1" runat="server">

<asp:GridView ID="GridView1" runat="server">

<asp:TemplateField>

<asp:CheckBox ID="chkAll" runat="server" OnCheckedChanged="chkAll_CheckedChanged" AutoPostBack="True" />

</HeaderTemplate>

<asp:CheckBox ID="chkItem" runat="server" />

</ItemTemplate>

</asp:TemplateField>

</Columns>

</asp:GridView>

</ContentTemplate>

</asp:UpdatePanel>

</div>

</form>

</body>

后台cs代码：

using System.Web.UI;

using System.Web.UI.WebControls;

using System.Web.UI.WebControls.WebParts;

using System.Web.UI.HtmlControls;

using System.Data.SqlClient;

public partial class Default3 : System.Web.UI.Page

{

protected void Page_Load(object sender, EventArgs e)

{

if (!IsPostBack)

{

string conStr = "server=192.168.0.118;database=Northwind;Uid=sa;pwd=";

string sql = "select * from Region";

SqlConnection con = new SqlConnection(conStr);

SqlDataAdapter sda = new SqlDataAdapter(sql, con);

DataSet ds = new DataSet();

sda.Fill(ds);

this.GridView1.DataSource = ds;

this.GridView1.DataBind();

sda.Dispose();

con.Close();

}

protected void chkAll_CheckedChanged(object sender, EventArgs e)

{

for (int i = 0; i < this.GridView1.Rows.Count; i++)

{

((CheckBox)this.GridView1.Rows[i].FindControl("chkItem")).Checked = ((CheckBox)this.GridView1.HeaderRow.FindControl("chkAll")).Checked;

}

本文转载自http://www.cnblogs.com/oec2003/archive/2007/11/09/954798.html，稍作修改~