17.2---#字棋（CC150）

牛客网的在线题。思路，比较简单。就是判断一下是否有连起来的1.

    public static boolean checkWon(int[][] board){
        boolean res = false;
        for(int i = 0; i < 3;i++){
            if(board[i][0] == 1 && board[i][1] == 1 && board[i][2] == 1){
                return true;
            }
            if(board[0][i] == 1 && board[1][i] == 1 && board[2][i] == 1 ){
                return true;
            }
        }
        if(board[0][0] == 1 && board[1][1] == 1 && board[2][2] == 1){
            return true;
        }
        
        if(board[0][2] == 1 && board[1][1] == 1 && board[2][0] == 1){
            return true;
        }
        
        return res;
    }