多维数组排序

依据第二列排序
#!/usr/bin/python
def takesecond(elem):
    return elem[1]
random = [(3,2,2), (3,4,1), (4,1,0), (1, 3,-1),(5,7,89),(5,2,0),(2,100,90),(2,100,2),(2,100,1),(2,100,0),(2,100,90)]
#ready=sorted(random,key=lambda x:(x[1],x[0]))
ready=sorted(random,key=lambda x: (x[0], x[1],x[2]),reverse=False)
print ready

依据第一列第二列第三列排序，都是升序：

#!/usr/bin/python

a=[[1,2,3,4],[4,2,3,4],[1,3,9,2],[1,3,6,7],[4,2,9,1000],[4,2,0,100000],[9,2,0,4]]
new=sorted(a, key = lambda x:(x[0],x[1],x[2]))
for i in new:
    print i