PHP错误杂记

  1. Notice: Only variables should be passed by reference in……

原因:The problem is, that end requires a reference, because it modifies the internal representation of the array (i.e. it makes the current element pointer point to the last element).

end函数: mixed end
( array &$array
)
你可以看到end的参数是一个引用(reference),而你只能把一个变量的引用作为一个参数传给函数,而你直接把explode('.',$name)作为参数传给end函数,所以才有这个提示。

原文地址:https://www.cnblogs.com/yolo-bean/p/7868258.html