LeetCode: Minimum Moves to Equal Array Elements

n-1个element加1相当于一个元素减1,那最少的move就是所有元素减去最小值之和

 1 public class Solution {
 2     public int minMoves(int[] nums) {
 3         int min = nums[0];
 4         for (int i = 0; i < nums.length; i++) {
 5             min = Math.min(min, nums[i]);
 6         }
 7         int ans = 0;
 8         for (int i = 0; i < nums.length; i++) {
 9             ans += nums[i] - min;
10         }
11         return ans;
12     }
13 }
原文地址:https://www.cnblogs.com/yingzhongwen/p/6100600.html