LeetCode: Fizz Buzz

   简单题

 1 public class Solution {
 2     public List<String> fizzBuzz(int n) {
 3         List<String> ans = new ArrayList<String>();
 4         for (int i = 1; i <= n; i++) {
 5             if (i % 3 == 0 && i % 5 == 0) {
 6                 ans.add("FizzBuzz");
 7             }
 8             else if (i % 3 == 0) {
 9                 ans.add("Fizz");
10             }
11             else if (i % 5 == 0) {
12                 ans.add("Buzz");
13             }
14             else ans.add(String.valueOf(i));
15         }
16         return ans;
17     }
18 }
原文地址:https://www.cnblogs.com/yingzhongwen/p/6086932.html