一开始dfs没过large, 网上看了别人的dp,哎,这题比较难。。
1 class Solution { 2 public: 3 int numDistinct(string S, string T) { 4 // Start typing your C/C++ solution below 5 // DO NOT write int main() function 6 vector<vector<int>> f(S.size()+1, vector<int>(T.size()+1)); 7 for (int i = 0; i <= S.size(); i++) f[i][0] = 0; 8 for (int i = 0; i <= T.size(); i++) f[0][i] = 0; 9 for (int i = 1; i <= S.size(); i++) { 10 if (S[i-1] == T[0]) f[i][1] = f[i-1][1]+1; 11 else f[i][1] = f[i-1][1]; 12 } 13 for (int i = 2; i <= S.size(); i++) { 14 for (int j = 2; j <= T.size(); j++) { 15 if (S[i-1] == T[j-1]) f[i][j] = f[i-1][j-1]+f[i-1][j]; 16 else f[i][j] = f[i-1][j]; 17 } 18 } 19 return f[S.size()][T.size()]; 20 } 21 };
c#
1 public class Solution { 2 public int NumDistinct(string s, string t) { 3 int[,] f = new int[s.Length+1, t.Length+1]; 4 for (int i = 1; i <= s.Length; i++) { 5 if (s[i-1] == t[0]) f[i, 1] = f[i-1, 1] + 1; 6 else f[i, 1] = f[i-1, 1]; 7 } 8 for (int i = 2; i <= s.Length; i++) { 9 for (int j = 2; j <= t.Length; j++) { 10 if (s[i-1] == t[j-1]) f[i, j] = f[i-1, j-1] + f[i-1, j]; 11 else f[i, j] = f[i-1, j]; 12 } 13 } 14 return f[s.Length, t.Length]; 15 } 16 }