Arpa is researching the Mexican wave.
There are n spectators in the stadium, labeled from 1 to n. They start the Mexican wave at time 0.
- At time 1, the first spectator stands.
- At time 2, the second spectator stands.
- ...
- At time k, the k-th spectator stands.
- At time k + 1, the (k + 1)-th spectator stands and the first spectator sits.
- At time k + 2, the (k + 2)-th spectator stands and the second spectator sits.
- ...
- At time n, the n-th spectator stands and the (n - k)-th spectator sits.
- At time n + 1, the (n + 1 - k)-th spectator sits.
- ...
- At time n + k, the n-th spectator sits.
Arpa wants to know how many spectators are standing at time t.
Input
The first line contains three integers n, k, t (1 ≤ n ≤ 109, 1 ≤ k ≤ n, 1 ≤ t < n + k).
Output
Print single integer: how many spectators are standing at time t.
Examples
input
10 5 3
output
3
input
10 5 7
output
5
input
10 5 12
output
3
Note
In the following a sitting spectator is represented as -, a standing spectator is represented as ^.
- At t = 0 ----------
number of standing spectators = 0. - At t = 1 ^--------- number of standing spectators = 1.
- At t = 2 ^^-------- number of standing spectators = 2.
- At t = 3 ^^^------- number of standing spectators = 3.
- At t = 4 ^^^^------ number of standing spectators = 4.
- At t = 5 ^^^^^----- number of standing spectators = 5.
- At t = 6 -^^^^^---- number of standing spectators = 5.
- At t = 7 --^^^^^--- number of standing spectators = 5.
- At t = 8 ---^^^^^-- number of standing spectators = 5.
- At t = 9 ----^^^^^- number of standing spectators = 5.
- At t = 10 -----^^^^^ number of standing spectators = 5.
- At t = 11 ------^^^^ number of standing spectators = 4.
- At t = 12 -------^^^ number of standing spectators = 3.
- At t = 13 --------^^ number of standing spectators = 2.
- At t = 14 ---------^ number of standing spectators = 1.
- At t = 15 ---------- number of standing spectators = 0.
题意：自己读一读就行
解法：暗中观察
1 #include<bits/stdc++.h> 2 using namespace std; 3 int main(){ 4 int n,k,t; 5 cin>>n>>k>>t; 6 if(k>=t){ 7 cout<<t<<endl; 8 }else if(t<=n){ 9 cout<<k<<endl; 10 }else if(n+k<=t){ 11 cout<<"0"<<endl; 12 }else{ 13 cout<<k-(t-n)<<endl; 14 } 15 return 0; 16 }