url decode 乱码

python  django框架

接收到字符ａ

a = u'%E7%88%B1%E4%BD%A0'

b = urllib.unquote(a)

u'xe7x88xb1xe4xbdxa0'

print b

ç±ä½

print 'xe7x88xb1xe4xbdxa0'

爱你

 

 

解决方法

a = u'%E7%88%B1%E4%BD%A0'

aa = str(a)

bb = urllib.unquote(aa)

print bb

爱你