剑指offer 面试35题

面试35题:

题目:复杂链表的复制

题:输入一个复杂链表(每个节点中有节点值,以及两个指针,一个指向下一个节点,另一个特殊指针指向任意一个节点),返回结果为复制后复杂链表的head。(注意,输出结果中请不要返回参数中的节点引用,否则判题程序会直接返回空)

解题思路一:“Python作弊法”

解题代码:

# -*- coding:utf-8 -*-
# class RandomListNode:
#     def __init__(self, x):
#         self.label = x
#         self.next = None
#         self.random = None
class Solution:
    # 返回 RandomListNode
    def Clone(self, pHead):
        # write code here
        import copy
        return copy.deepcopy(pHead)

解题思路二:分解法。详见剑指offer P188

解题代码:

# -*- coding:utf-8 -*-
# class RandomListNode:
#     def __init__(self, x):
#         self.label = x
#         self.next = None
#         self.random = None
class Solution:
    # 返回 RandomListNode
    def Clone(self, pHead):
        # write code here
        if  pHead==None:
            return None
        self.CloneNodes(pHead)
        self.ConnectRandomNodes(pHead)
        return self.ReconnectNodes(pHead)
    
    def CloneNodes(self,pHead):
        '''
        复制原始链表的每个结点, 将复制的结点链接在其原始结点的后面
        '''
        pNode=pHead
        while pNode:
            pCloned=RandomListNode(0)
            pCloned.label=pNode.label
            pCloned.next=pNode.next

            pNode.next=pCloned
            pNode=pCloned.next
    
    def ConnectRandomNodes(self,pHead):
        '''
        将复制后的链表中的克隆结点的random指针链接到被克隆结点random指针的后一个结点
        '''
        pNode=pHead
        while pNode:
            pCloned=pNode.next
            if pNode.random!=None:
                pCloned.random=pNode.random.next
            pNode=pCloned.next

    def ReconnectNodes(self,pHead):
        '''
        拆分链表:将原始链表的结点组成新的链表, 复制结点组成复制后的链表
        '''
        pNode=pHead
        pClonedHead=pClonedNode=pNode.next
        pNode.next = pClonedNode.next
        pNode=pNode.next
        while pNode:
            pClonedNode.next=pNode.next
            pClonedNode=pClonedNode.next
            pNode.next=pClonedNode.next
            pNode=pNode.next
        return pClonedHead


解法三:递归法,强烈推荐。

# -*- coding:utf-8 -*-
# class RandomListNode:
#     def __init__(self, x):
#         self.label = x
#         self.next = None
#         self.random = None
class Solution:
    # 返回 RandomListNode
    def Clone(self, pHead):
        # write code here
        if  pHead==None:
            return None
        newNode=RandomListNode(pHead.label)
        newNode.random=pHead.random
        newNode.next=self.Clone(pHead.next)
        return newNode
原文地址:https://www.cnblogs.com/yanmk/p/9220525.html