知识点补充：有意思的函数合集

函数的返回值

def f1():
    print('f1')
    return f3()

def f3():
    print('f3')

a = f1()
print(a)
#输出结果为
f1
f3
None #注意此处的输出结果

函数的层次

def func(num):
    def inner():
        print(num)
    return inner

result = []
for i in range(10):
    f = func(i)
    result.append(f)

print(i)
print(result)
v1 = result[0]() #注意此处运行的是哪一个函数
v2 = result[9]()
print(v1,v2)
#输出结果为
9
[<function func.<locals>.inner at 0x0000020603166DC0>, <function func.<locals>.inner at 0x0000020603166E50>, <function func.<locals>.inner at 0x0000020603166EE0>, <function func.<locals>.inner at 0x0000020603166F70>, <function func.<locals>.inner at 0x000002060317E040>, <function func.<locals>.inner at 0x000002060317E0D0>, <function func.<locals>.inner at 0x000002060317E160>, <function func.<locals>.inner at 0x000002060317E1F0>, <function func.<locals>.inner at 0x000002060317E280>, <function func.<locals>.inner at 0x000002060317E310>]
0
9
None None

推导式中循环的 i 值

v =[lambda:i for i in range(10)]
result = v[5]()
print(result)
#输出结果为
9

不太清楚 func(name = None)的具体含义