JS响应回车事件

(1)监听某个输入框

    $('#search_input').bind('keyup', function(event) {

        if (event.keyCode == "13") {

            //回车执行查询

            $('#search_button').click();

        }

});

(2)监听某个区域

$("#queryTable").bind("keydown",function(e){

          // 兼容FF和IE和Opera   

             var theEvent = e || window.event;   

             var code = theEvent.keyCode || theEvent.which || theEvent.charCode;   

             if (code == 13) {   

                 //回车执行查询

            $("#queryButton").click();

        }   

});

(3)监听body

//回车事件

    document.onkeydown = function (event) {

        var e = event || window.event;

        if (e && e.keyCode == 13) { //回车键的键值为13

            $("#login").click(); //调用登录按钮的登录事件

        }

    };
原文地址:https://www.cnblogs.com/yang-blogs/p/9722071.html