LaTex数学公式

排版方式:

行级元素(inline):使用$...$,表示公式的首尾
块级元素(displayed):使用$$...$$,默认居中显示


LaTex数学符号表

小写希腊字母

大写希腊字母

数学函数名

二元关系符

二元运算符

大尺寸运算符

箭头

定界符

大尺寸定界符

其它符号

AMS二元关系符

AMS二元否定关系符和箭头


举例:

$$ 
x_i^2 
$$

[x_i^2 ]

$$ 
log_2 x 
$$

[log_2 x ]

$$ 
10^{10} 
$$

[10^{10} ]

$$
 {1+2} 
$$

[ {1+2} ]

$$
frac{1+1}{2}+1
$$

[frac{1+1}{2}+1 ]

$$
sum_1^n
$$

[sum_1^n ]

$$
int_1^n
$$

[int_1^n ]

$$
lim_{x	oinfty}
$$

[lim_{x oinfty} ]

$$
egin{matrix}
        1 & x & x^2 \
        1 & y & y^2 \
        1 & z & z^2 \
end{matrix}
$$

[egin{matrix} 1 & x & x^2 \ 1 & y & y^2 \ 1 & z & z^2 \ end{matrix} ]

$$
h(	heta) = sum_{j=0}^n	heta_jx_j
$$

[h( heta) = sum_{j=0}^n heta_jx_j ]

$$
frac{partial J(	heta)}{partial	heta_j} = -frac{1}{m}sum_{i=0}^m(y^i-h_	heta(x^i))x_j^i
$$

[frac{partial J( heta)}{partial heta_j} = -frac{1}{m}sum_{i=0}^m(y^i-h_ heta(x^i))x_j^i ]

$$
f(n) = 
	egin{cases}
	n/2,  & 	ext{if $n$ is even} \
	3n+1, & 	ext{if $n$ is odd} 
	end{cases}
$$

[f(n) = egin{cases} n/2, & ext{if $n$ is even} \ 3n+1, & ext{if $n$ is odd} end{cases} ]

$$
left{
	egin{array}{}
		a_1x+b_1y+c_1z = d_1\
		a_2x+b_2y+c_2z = d_2\
        	 a_3x+b_3y+c_3z = d_3
	end{array}

ight.
$$

[left{ egin{array}{} a_1x+b_1y+c_1z = d_1\ a_2x+b_2y+c_2z = d_2\ a_3x+b_3y+c_3z = d_3 end{array} ight. ]

$$
X = left(
	egin{matrix}
		x_{11} &x_{12}&cdots&x_{1d}\
		x_{21} &x_{22}&cdots&x_{2d}\
		vdots&vdots&ddots&vdots\
		x_{m1}&x_{m2}&cdots&x_{md}
	end{matrix}
	
ight)
  = left(
 	egin{matrix}
 		x_1^T\
 		x_2^T\
 		vdots\
 		x_m^T\
 	end{matrix}
      
ight)
$$

[X = left( egin{matrix} x_{11} &x_{12}&cdots&x_{1d}\ x_{21} &x_{22}&cdots&x_{2d}\ vdots&vdots&ddots&vdots\ x_{m1}&x_{m2}&cdots&x_{md} end{matrix} ight) = left( egin{matrix} x_1^T\ x_2^T\ vdots\ x_m^T\ end{matrix} ight) ]

$$
egin{align}
frac{partial J(	heta)}{partial 	heta_j}
	& = -frac{1}{m}sum_{i=0}^m(y^i-h_	heta(x^i))frac{partial}{partial	heta_j}(y^i-h_	heta(x^i))  \
	& = -frac{1}{m}sum_{i=0}^m(y^i-h_	heta(x^i))frac{partial}{partial	heta_j}(sum_{j=0}^n	heta_jx_j^i-y^i)  \
	& = -frac1msum_{i=0}^m(y^i-h_	heta(x^i))x_i^j
 end{align}
$$

[egin{align} frac{partial J( heta)}{partial heta_j} & = -frac{1}{m}sum_{i=0}^m(y^i-h_ heta(x^i))frac{partial}{partial heta_j}(y^i-h_ heta(x^i)) \ & = -frac{1}{m}sum_{i=0}^m(y^i-h_ heta(x^i))frac{partial}{partial heta_j}(sum_{j=0}^n heta_jx_j^i-y^i) \ & = -frac1msum_{i=0}^m(y^i-h_ heta(x^i))x_i^j end{align} ]

$$
sqrt{x^2+sqrt{y}}  \
sqrt[3]{2} \
$$

[sqrt{x^2+sqrt{y}} \ sqrt[3]{2} \ ]

$$
overline{m+n}  qquad 
underline{m+n}
$$

[overline{m+n} qquad underline{m+n} ]

$$
underbrace{a+b+cdots+z}_{26}
$$

[underbrace{a+b+cdots+z}_{26} ]

$$
vec{a} quad
overrightarrow{AB}
$$

[vec{a} quad overrightarrow{AB} ]

$$
v = sigma_1 cdot sigma_2 	au_1 cdot	au_2
$$

[v = sigma_1 cdot sigma_2 au_1 cdot au_2 ]

$$
lim_{x 
ightarrow 0} frac{sin x}{x}=1
$$

[lim_{x ightarrow 0} frac{sin x}{x}=1 ]

$$
mathop{min_{G} max_{D}}
$$

[mathop{min_{G} max_{D}} ]

设置大小括号

Reference:

一份不太简短的LaTex介绍

原文地址:https://www.cnblogs.com/xxxxxxxxx/p/10977771.html