HDU1060

n^n=10^(  n*log10( n )  );

View Code
 1 /*
 2 n^n 的最高位
 3 */
 4 #include<stdio.h>
 5 #include<stdlib.h>
 6 #include<string.h>
 7 #include<iostream>
 8 #include<algorithm>
 9 #include<queue>
10 #include<map>
11 #include<math.h>
12 using namespace std;
13 const int maxn = 1005;
14 const int inf = 0x7fffffff;
15 int main(){
16     int T;
17     scanf("%d",&T);
18     while( T-- ){
19         int n;
20         scanf("%d",&n);
21         double tmp1,tmp2;
22         int tmp;
23         tmp1=n*1.0*log10(1.0*n);
24         tmp2=tmp1-(floor)(tmp1);//(int)强制转换 WA!
25         printf("%.0lf\n",(floor)(pow(10.0,tmp2)));
26     }
27     return 0;
28 }
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原文地址:https://www.cnblogs.com/xxx0624/p/2818623.html