React 在body上绑定事件以及阻止事件冒泡

<!DOCTYPE html>
<html>

<head>
    <meta charset="UTF-8" />
    <title>React 在body上绑定事件以及阻止事件冒泡</title>
    <script src="https://unpkg.com/react@16/umd/react.development.js"></script>
    <script src="https://unpkg.com/react-dom@16/umd/react-dom.development.js"></script>
    <script src="https://unpkg.com/babel-standalone@6.15.0/babel.min.js"></script>
    <style>
        html{height: 100%;}
        body{height: 100%;background-color: rgba(0,0,0,0.2);}
        .m-outer{background-color: red;}
    </style>
</head>

<body>
    <div id="root"></div>
    <script type="text/babel">
        class Toggle extends React.Component {
        constructor(props) {
          super(props);
          this.state = {isToggleOn: true};
 
          // 这个绑定是必要的,使`this`在回调中起作用
          this.handleClick = this.handleClick.bind(this);
        }

        componentDidMount() { 
            document.body.addEventListener('click', e => { 
                if (e.target && e.target.matches('#m-btn')) { 
                    return; 
                }             
                console.log('body');
            });             
        } 

        componentWillUnmount() { 
            document.body.removeEventListener('click');
        }                

        handleClick() {
          this.setState(prevState => ({
            isToggleOn: !prevState.isToggleOn
          }));
        }
 
        render() {
          return (
              <button onClick={this.handleClick} id="m-btn">
                {this.state.isToggleOn ? 'ON' : 'OFF'}
              </button>
          );
        }
      }
 
      ReactDOM.render(
        <Toggle />,
        document.getElementById('root')
      );
    </script>
</body>

</html>
原文地址:https://www.cnblogs.com/xutongbao/p/9924745.html