例2-7+例2-8


#include<stdio.h>
int main(void)
{
    int denominator,flag,i,n;
    double item,sum;

    printf("Enter n:");
    scanf("%d",&n);
    flag=1;
    denominator=1;
    sum=0;
    for(i=1;i<=n;i++){
        item=flag*1.0/denominator;
        sum=sum+item;
        flag=-flag;
        denominator=denominator+2;
    }
    printf("sum=%f
",sum);

    return 0;
}


/*
计算1+2+3+...+n*/ #include<stdio.h> int main(void) { int i,n,sum; printf("Enter n:"); scanf("%d",&n); sum=0; for(i=1;i<=n;i++){ sum=sum+i; } /*输出累加和*/ printf("Sum of numbers from 1 to %d is %d ",n,sum); return 0; }

原文地址:https://www.cnblogs.com/xuqiongxiang/p/3349381.html