生成器面试题

def add(n,i):
    return n+i

def test():
    for i in range(4):
        yield i

g=test()
for n in [1,10]: #n=10
    g=(add(n,i) for i in g)

    # 第一次循环:
    # g=(add(n,i) for i in test())

    # 第二次循环:
    # g=(add(n, i) for i in (add(n,i) for i in test()))

# print(n)
res=list(g)

# 迭代器1=(add(n,i) for i in test())
# for i in 迭代器1: #i=next(迭代器1) i=11
#     add(n, i) #add(10,11)

print(res)
#A. res=[10,11,12,13]
#B. res=[11,12,13,14]
#C. res=[20,21,22,23]
#D. res=[21,22,23,24]
原文地址:https://www.cnblogs.com/xuqidong/p/13732705.html