[leetcode.com]算法题目

Given a sorted linked list, delete all duplicates such that each element appear only once.

For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.

 1 /**
 2  * Definition for singly-linked list.
 3  * struct ListNode {
 4  *     int val;
 5  *     ListNode *next;
 6  *     ListNode(int x) : val(x), next(NULL) {}
 7  * };
 8  */
 9 class Solution {
10 public:
11     ListNode *deleteDuplicates(ListNode *head) {
12         // Start typing your C/C++ solution below
13         // DO NOT write int main() function
14         ListNode *p;
15         p = head;
16         if(!p) return head;
17         
18         while(p->next){
19             if(p->next->val == p->val){
20                 ListNode *q;
21                 q=p->next;
22                 p->next = q->next;
23                 delete q;
24             }
25             else{
26                 p = p->next;
27         
28             }        
29         }
30         
31         return head;
32     }
33 };
View Code

思路:考察链表的基本操作,只要注意细节就没问题。

原文地址:https://www.cnblogs.com/xuning/p/3315755.html