第三十篇 玩转数据结构——字典树(Trie)

 
 
 
1.. Trie通常被称为"字典树"或"前缀树"
  • Trie的形象化描述如下图:
  • Trie的优势和适用场景
2.. 实现Trie
  • 实现Trie的业务无逻辑如下:
  • import java.util.TreeMap;
    
    public class Trie {
    
        private class Node {
    
            public boolean isWord;
            public TreeMap<Character, Node> next;
    
            // 构造函数
            public Node(boolean isWord) {
                this.isWord = isWord;
                next = new TreeMap<>();
            }
    
            // 无参数构造函数
            public Node() {
                this(false);
            }
        }
    
        private Node root;
        private int size;
    
        // 构造函数
        public Trie() {
            root = new Node();
            size = 0;
        }
    
        // 实现getSize方法,获得Trie中存储的单词数量
        public int getSize() {
            return size;
        }
    
        // 实现add方法,向Trie中添加新的单词word
        public void add(String word) {
    
            Node cur = root;
            for (int i = 0; i < word.length(); i++) {
                char c = word.charAt(i);
                if (cur.next.get(c) == null) {
                    cur.next.put(c, new Node());
                }
                cur = cur.next.get(c);
            }
            if (!cur.isWord) {
                cur.isWord = true;
                size++;
            }
        }
    
        // 实现contains方法,查询Trie中是否包含单词word
        public boolean contains(String word) {
    
            Node cur = root;
            for (int i = 0; i < word.length(); i++) {
                char c = word.charAt(i);
                if (cur.next.get(c) == null) {
                    return false;
                }
                cur = cur.next.get(c);
            }
            return cur.isWord;  // 好聪明
        }
    
        // 实现isPrefix方法,查询Trie中时候保存了以prefix为前缀的单词
        public boolean isPrefix(String prefix) {
    
            Node cur = root;
            for (int i = 0; i < prefix.length(); i++) {
                char c = prefix.charAt(i);
                if (cur.next.get(c) == null) {
                    return false;
                }
                cur = cur.next.get(c);
            }
            return true;
        }
    }

3.. Trie和简单的模式匹配

  • 实现的业务逻辑如下:
  • import java.util.TreeMap;
    
    class WordDictionary {
    
        private class Node {
    
            public boolean isWord;
            public TreeMap<Character, Node> next;
    
            public Node(boolean isWord) {
                this.isWord = isWord;
                next = new TreeMap<>();
            }
    
            public Node() {
                this(false);
            }
    
        }
    
        /**
         * Initialize your data structure here.
         */
        private Node root;
    
        public WordDictionary() {
            root = new Node();
        }
    
        /**
         * Adds a word into the data structure.
         */
        public void addWord(String word) {
            Node cur = root;
            for (int i = 0; i < word.length(); i++) {
                char c = word.charAt(i);
                if (cur.next.get(c) == null) {
                    cur.next.put(c, new Node());
                }
                cur = cur.next.get(c);
            }
            cur.isWord = true;
        }
    
        /**
         * Returns if the word is in the data structure. A word could contain the dot character '.' to represent any one letter.
         */
        public boolean search(String word) {
            return match(root, word, 0);
        }
    
        private boolean match(Node node, String word, int index) {
            if (index == word.length()) {
                return node.isWord;
            }
    
            char c = word.charAt(index);
            if (c != '.') {
                if (node.next.get(c) == null) {
                    return false;
                }
                return match(node.next.get(c), word, index + 1);
            } else {
                for (char nextChar : node.next.keySet()) {
                    if (match(node.next.get(nextChar), word, index + 1)) {
                        return true;
                    }
                }
                return false;
            }
        }
    }
原文地址:https://www.cnblogs.com/xuezou/p/9303859.html