bzoj1081

题解:

先暴力找规律

然后就一加一减的枚举

代码:

#include<bits/stdc++.h>
using namespace std;
int n,m,f[55],p[55];
int main()
{
    scanf("%d%d",&n,&m);
    for (int i=1;i<=n;i++)f[i]=1,p[i]=0;
    while (1)
     {
         for (int i=1;i<=n;i++)
          if (p[i]>9)putchar(p[i]-10+'A');
          else putchar(p[i]+'0');
         puts(""); 
         int i=1;
         while ((p[i]+f[i]<0||p[i]+f[i]>=m)&&i<=n)i++;
         p[i]+=f[i];
         if (i>n)return 0;
         for (i-=1;i;i--)f[i]=-f[i];
     }
}
原文地址:https://www.cnblogs.com/xuanyiming/p/8456204.html