题解:
只要输出n/2即可
代码:
#include<cstdio> #include<cmath> #include<cstring> #include<algorithm> using namespace std; int T,n,x,y; int main() { scanf("%d",&T); while (T--) { scanf("%d",&n); for (int i=1;i<=3*n/2;i++)scanf("%d%d",&x,&y); printf("%d ",n/2); } return 0; }