u Calculate e
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 25494 Accepted Submission(s): 11312
Problem Description
A simple mathematical formula for e is
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
Sample Output
n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
Source
Greater New York 2000
Recommend
JGShining
#include <stdio.h>
int jc(int n)
{
int i,sum=1;
if(n==0)
return 1;
if(n>0)
{
for(i=1;i<=n;i++)
sum*=i;
return sum;
}
}
int main()
{
int i,j,e,t,n=9;
double sum=0;
printf("n e
");
printf("- -----------
");
printf("0 1
");
printf("1 2
");
printf("2 2.5
");
for(j=3;j<=n;j++)
{
sum=0;
for(i=0;i<=j;i++)
{
t=jc(i);
sum+=1.0/t;
}
printf("%d %.9lf
",j,sum);
}
return 0;
}