JQuery 获取URL参数

 1 jQuery.extend({
 2 /**
 3 * Returns get parameters. 返回获取参数。
 4 *
 5 * If the desired param does not exist, null will be returned  如果所需的参数不存在,将会返回null
 6 *
 7 * @例子 value = $.getURLParam("paramName");
 8 */ 
 9  getURLParam: function(strParamName,url){
10       var strReturn = "";
11       var strHref = url||window.location.href;
12       var bFound=false;
13       
14       var cmpstring = strParamName + "=";
15       var cmplen = cmpstring.length;
16 
17       if ( strHref.indexOf("?") > -1 ){
18         var strQueryString = strHref.substr(strHref.indexOf("?")+1);
19         var aQueryString = strQueryString.split("&");
20         for ( var iParam = 0; iParam < aQueryString.length; iParam++ ){
21           if (aQueryString[iParam].substr(0,cmplen)==cmpstring){
22             var aParam = aQueryString[iParam].split("=");
23             strReturn = aParam[1];
24             bFound=true;
25             break;
26           }
27           
28         }
29       }
30       if (bFound==false) return null;
31       return strReturn;
32     }
33 });
原文地址:https://www.cnblogs.com/xjbBill/p/7306922.html