1001. Reverse Root

Time Limit: 2.0 second
Memory Limit: 64 MB

The problem is so easy, that the authors were lazy to write a statement for it!

Input

The input stream contains a set of integer numbers A_i (0 ≤ A_i ≤ 10¹⁸). The numbers are separated by any number of spaces and line breaks. A size of the input stream does not exceed 256 KB.

Output

For each number A_i from the last one till the first one you should output its square root. Each square root should be printed in a separate line with at least four digits after decimal point.

Sample

input	output
1427 0 876652098643267843 5276538	2297.0716 936297014.1164 0.0000 37.7757

 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cmath>
 4 #include <vector>
 5 using namespace std;
 6 
 7 int main(){
 8 
 9     double n;
10     vector <double> ans;
11     while(cin >> n) ans.push_back(sqrt(n));
12     for(int i = ans.size()-1; i>= 0 ; i--)
13         printf("%.4f\n",ans[i]);
14     return 0;
15 }